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©2006-2009 *Verticae
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Submitted: June 13, 2006
Image Size: 805 KB
Resolution: 950×1226
Comments: 132
Favourites & Collections: 764 [who?]

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Artist's Comments

I'm not the only one who can't see why
See your life and death reduce into a product line


Personal piece. Wacom Intuos3, PSCS2, about 3 days. Stack from =resurgere and personal collection.

Dedicated to sheknowswhosheis.
Daily Deviation, 2006-06-14

Daily DeviationDark and mysterious :Product Line by *Verticae. If you don't have a look at this in full view, you'll miss the incredible textures and details in this piece. (Suggested by $zilla774 and Featured by `nighty)

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Comments


i like this one ..... good work it's really dark ....keep on

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It's only after we've lost everything .. that we're free to do anything ...
amazing. I really like the colours and textures.
:aww: you dedicated it to me :flirty:
though I'm a he, not a she. I'm quite sure of that.

It looks great all over the place

And I know that hole in the wall! :D resurgere for the win
goodiful workiful, vertiful

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Oh wow ... Lot of work on it ! Very good !
Great work on texture, it's very dark, I love it !

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My Online Portfolio | My Photos Gallery | My Stock |
Uh... 4 comments and 12 favourites?

This DEFINATELY deserves more than that. It's incredible.

:+fav:

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Signatures are for IDIOTS. Oh... Wait...
wow, this is awesome! very evil :clap:

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"The government is not the solution to our problems, the government is the problem"

Come To My Kingdom...
Just when I think I've lost interest in dark art, along comes a work like this.

Outstanding texture use and composition. Something that detracts from the image slightly for me though is the back/waist. It's not so much the lack of detail but that it seems to suddenly "join up" with the dress with not a lot of blending between the two. A bit of progressive shading might help a lot there? Other than that though, this is great work.
Brilliant work. Maybe the part below the waist could have been textured a bit more, but in any case, this is awesome.

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Did you know that:
E^2 = p^2c^2)+([<delta>m^2]c^4.
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c")].
when p=0 (in eq 1, or 2, whichever you find simpler)
E=mc^2........
(In reality, p can never=0, so E should, realistically not be =mc^2, )
Amazing. Exceptional use of textures and great tones. Amazing lighting too! :clap:

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